izaya5kk izaya5kk
  • 23-05-2020
  • Mathematics
contestada

find the number of real solutions of the equation x^2+10x+35=0 using the discriminant:(b^2-4ac)

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mdagamac mdagamac
  • 23-05-2020

Answer: No real roots or solutions

Step-by-step explanation:

X^2+10x+35=0 using this equation you can tell that a=1, b=10, and c=35. Using the numbers for the formula,

b^2 - 4ac, it will look like this... 10^2-4(1)(35). Next step is the exponent. It will look like this now, 100-4(1)(35), the next step is to multiply. 100-140= -40. When the discriminant is negative, there are no real roots, or solutions.

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