Respuesta :

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[tex]\ln x+2\ln y-\ln z=\ln x+\ln y^2-\ln z=\ln\dfrac{xy^2}{z}\\\\Used:\ln a+\ln b=\ln(a\cdot b}\\\\\ln a-\ln b=\ln\dfrac{a}{b}\\\\n\ln a=\ln a^n[/tex]

Answer:

ln [tex]\frac{xy^{2} }{z}[/tex]

Step-by-step explanation:

just took the test :D

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