Respuesta :

assuming is a 9 inch side.

[tex]\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}\qquad \begin{cases} s=length~of\\ \qquad a~side\\ -------\\ s=9 \end{cases}\implies A=\cfrac{9^2\sqrt{3}}{4}\implies A=\cfrac{81\sqrt{3}}{4}[/tex]

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