asadnaseem134ovjt9l asadnaseem134ovjt9l
  • 24-03-2018
  • Mathematics
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how can i solve this question ?

how can i solve this question class=

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Аноним Аноним
  • 24-03-2018
The parallel lines have created similar triangles. So, the following is true:
[tex] \frac{20}{30} = \frac{AC}{AE} = \frac{2}{3} [/tex]
this means that [tex] \frac{CE}{AE} = \frac{1}{3} [/tex]

Because those sides are shared we can create the following proportion:
[tex] \frac{1}{3} = \frac{4}{h} [/tex]

Cross - multiply and we get h = 12

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