alowery515
alowery515 alowery515
  • 23-03-2018
  • Mathematics
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Bladerunner1976
Bladerunner1976 Bladerunner1976
  • 23-03-2018
Since they are independent events to find the probability of both is P(A) * P(B)

P(A) = P(Heads) = [tex] \frac{1}{2} [/tex]
P(B) = P(Roll ≥ 4) = [tex] \frac{3}{6} = \frac{1}{2} [/tex]

Now multiply those fractions together

[tex] \frac{1}{2} * \frac{1}{2} = \frac{1}{4} [/tex] = P(Heads & ≥ 4)
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