averyisbosstango averyisbosstango
  • 22-03-2018
  • Mathematics
contestada

Factor completely 6a^3-10a^2+3a-5

Respuesta :

MrsStrong
MrsStrong MrsStrong
  • 17-01-2019

Answer:

[tex](2a^2+1)(3a-5)[/tex]

Step-by-step explanation:

Since it has 4 terms, the cubic expression can be factored using grouping. Use parenthesis to group terms in two and factor by GCF.

[tex]6a^3-10a^2+3a-5\\(6a^3-10a^2)(3a-5)\\2a^2(3a-5)+1(3a-5)[/tex]

Since 3a-5 repeats, the factoring is complete and correct. The factors are then [tex](2a^2+1)(3a-5)[/tex].

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