peruvianquinone peruvianquinone
  • 26-02-2018
  • Chemistry
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How much heat energy is absorbed when 6.83 kg of water is heated from 10.0 0C to 47.0 0C. The specific heat of water is 4.184 J/g 0C.

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kenmyna
kenmyna kenmyna
  • 07-03-2018
Heat  energy=   mass x  specific  heat   x  change  in  temperature
change   in  temperature=47.0=10.0=  37  degrees
convert  mass  in  G =  6.83x1000=6830g
Heat  energy  is  hence=  6830  x 4.184 j/g/degrees  x  37=1057338.64 j  or   1057.33864Kj

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