thetrojantv
thetrojantv thetrojantv
  • 25-02-2018
  • Mathematics
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carlosego
carlosego carlosego
  • 25-02-2018
You should see the denominator of the function in this case.
 6x ^ 2-7x-3
 We see where the denominator becomes zero:
 6x ^ 2-7x-3 = 0
 x1 = 3/2
 x2 = -1 / 3
 The function is discontinuous in those two points.
 Therefore, it has vertical asymptotes in:
 x1 = 3/2
 x2 = -1 / 3
 answer:
 has vertical asymptotes in:
 x1 = 3/2
 x2 = -1 / 3
 option 1
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