jclark4231 jclark4231
  • 23-02-2018
  • Mathematics
contestada

what is the factored form of 64g^3+8

what is the factored form of 64g38 class=

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jdoe0001 jdoe0001
  • 23-02-2018
[tex]\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad (a+b)(a^2-ab+b^2)= a^3+b^3 \\\\ a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad (a-b)(a^2+ab+b^2)= a^3-b^3\\\\ -------------------------------\\\\ 64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3 \\\\\\ (4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4] \\\\\\ (4g+2)(16g^2-8g+4)[/tex]
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