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  • 22-02-2018
  • Mathematics
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mathmate
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  • 23-02-2018
Given quadratic equation[tex][/tex][tex]x^2+6x+6=0[/tex]
Using the usual conventions, 
a=1, b=6, c=6
Apply the quadratic formula,
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
substitute a,b & c with numerical values,
[tex]x=\frac{-6\pm\sqrt{6^2-4(1)(6)}}{2(1)}[/tex]
simplify:
[tex]x=\frac{-6\pm\sqrt{12}}{2}[/tex]
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