check the picture below.
[tex]\bf \cfrac{10x-2}{7x}=\cfrac{8x}{5x+3}\implies (10x-2)(5x+3)=(7x)(8x)
\\\\\\
50x^2-10x+30x-6=56x^2\implies 0=6x^2-20x+6
\\\\\\
0=3x^2-10x+3\implies 0=(3x-1)(x-3)\implies x=
\begin{cases}
\frac{1}{3}\\\\
3
\end{cases}[/tex]
