AprilKitties
AprilKitties AprilKitties
  • 22-01-2018
  • Mathematics
contestada

What is sin 45 expressed as a square root?

Respuesta :

Zinethar
Zinethar Zinethar
  • 22-01-2018
sin(45) is equal to [tex] \frac{ \sqrt{2} }{2} [/tex] in degrees.
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Аноним Аноним
  • 03-06-2021

Answer:

√2 / 2

Step-by-step explanation:

If you draw a right triangle with sides = 1, then by Pythagoras the diagonal is sqrt(2). The angles are 45, 45, and 90. Sine = Opposite / Hypotenuse So sin 45 = 1 / sqrt(2). To eliminate the square root in the denominator, multiply numerator and denominator by sqrt(2).

This leaves it unchanged since sqrt(2) / sqrt(2) = 1. So sin 45 = sqrt(2)/2.

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