djlaskowski6926 djlaskowski6926
  • 25-11-2017
  • Mathematics
contestada

Which values for b make the polynomial 16z2 + bz + 81 a perfect square trinomial?

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zeeshanturi72 zeeshanturi72
  • 25-11-2017
as (a+b)^2 = a^2 + 2*a*b +b^2 .......(i)

here we have 
16z^2 + bz + 81 which can be written as (4z)^2 +  bz +9^2

from (i) we can see that in order to be perfect square bz should be
bz = 2* (4z) * (9)
bz= 72z

dividing z on both sides we get
b=72
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