1- -y^2+6y+x-9=0 2- 6y=x+27 we solve by substituting from the 2nd equation we get x=6y-27 substituting in equation 1 -y^2+6y+(6y-27)-9=0 -y^2+12y-36=0 y^2-12y+36=0 (y-6)(y-6)=0 y=6 since x=6y-27 x=36-27=9 the point of intersection of only soultion is (9,6)
