The weekly revenue for a company is r equals negative 3 p squared plus 70 p plus 988r=−3p2+70p+988, where p is the price of the company's product. use the discriminant to find whether there is a price for which the weekly revenue would be $18001800.

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24-10-2017
Mathematics

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The weekly revenue for a company is r equals negative 3 p squared plus 70 p plus 988r=−3p2+70p+988, where p is the price of the company's product. use the discriminant to find whether there is a price for which the weekly revenue would be $18001800.

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Kalahira Kalahira · Answer 1 · 2017-11-04T13:42:43+01:00

1800 = -3p^2+70p+988 0 = -3p^2+70p - 812 Using the discriminant means taking the section of the quadratic formula: âšâ€‹(b^2)â’4ac And by plugging in the values of our formula we get: âšâ€‹(70^2)â’4*-3*-812 Which yields: âšâ€‹4900 â’ 9744 Since this is a square root of a negative number, it says there is no real solution for the formula, which makes sense because the formula is a quadratic that is pointing downwards (a = -3p^2) and underneath the number line (c = -812). â€‹ â€‹â€‹ â€‹â€‹

The weekly revenue for a company is r equals negative 3 p squared plus 70 p plus 988r=−3p2+70p+988​, where p is the price of the​ company's product. use the discriminant to find whether there is a price for which the weekly revenue would be ​$18001800.

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The weekly revenue for a company is r equals negative 3 p squared plus 70 p plus 988r=−3p2+70p+988, where p is the price of the company's product. use the discriminant to find whether there is a price for which the weekly revenue would be $18001800.