Respuesta :

D3xt3R
We know that

[tex]1~mol[/tex] have [tex]6.02\times10^{23}~molecules[/tex]

therefore

[tex]0.589~mol[/tex] have [tex]0.589*6.02\times10^{23}~molecules\approx3.55\times10^{23}~molecules[/tex]

3.55 x 10^23 molecules are found in 0.589 of N2.

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