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Let f(x) = 5x + 12. Find f−1(x).

A: 12x + 5
B: 1 over quantity 5 x plus 12
C: 5 over quantity x minus 12
D: quantity of x minus 12 over 5

Respuesta :

naǫ
[tex]f(x)=5x+12 \\ \\ \hbox{solve for x:} \\ y=5x+12 \\ y-12=5x \\ x=\frac{y-12}{5} \\ \\ \hbox{swap x and y:} \\ y=\frac{x-12}{5} \\ \\ \boxed{f^{-1}(x)=\frac{x-12}{5}}[/tex]

The answer is D.

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