larosamitchellou27f9 larosamitchellou27f9
  • 25-08-2017
  • Mathematics
contestada

Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5 in. And whose upper base is a square with a side 3in and whose altitude is 12in

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yahirvaladez4
yahirvaladez4 yahirvaladez4
  • 25-08-2017
the volume of the frustum =(1/3)h[a1+a2]+√(a1 a2) where a1=bottom area,a2=top area and h=height
a1=100sa.inch
a2=25 sq.inch and
h=12inch
so the volume =(1/3)(12)[100+25+
√(100*25)]
=4*[125+50]
=4*175=700 cubic inches or [inch cubed]
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Аноним Аноним
  • 25-08-2017
by similar triangles 3/5 = x / 12   
x = 36/5 = 7.2

 volume of frustum  = 1/3 * 5^2 * 12 - 1/3 * 3^2 * 7.2

=  100-21.6

= 78.4 in^3
Answer Link

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