Answer:
[tex]10+10\sqrt3[/tex]
Step-by-step explanation:
[tex]\text{Solution:}\\\text{1. Given that }\angle\text{XYZ}=\angle\text{YXZ, this means }\triangle\text{XYZ is isosceles.}\\\therefore\ \text{YZ = XZ = 10}[/tex]
[tex]\text{In triangle WYZ,}\\\text{tan}30^\circ=\dfrac{\text{YZ}}{\text{WZ}}\\\\\text{or, }\dfrac{1}{\sqrt3}=\dfrac{10}{\text{WZ}}\\\\\text{or, WZ}=10\sqrt3[/tex]
[tex]\therefore\ \text{WX = WZ + XZ = }10\sqrt3+10\approx27.32[/tex]
