Answer:
1/π
Step-by-step explanation:
solⁿ L=lim(x→π) (cosx + sin(2x) +1)/(x² - π²) , 0/0 form
Apply L’Hospital rule
L=lim(x→π) (- sinx + 2cos(2x) +0)/(2x -0)
L=(-sin(π) + 2cos(2π) )/2π
L=(0 + 2×1)/2π
L=2/2π
L=1/π
