colleengrogan2otkqa1 colleengrogan2otkqa1
  • 24-07-2017
  • Physics
contestada

3.6-kg chihuahua charges at a speed of 3.3 m/s what is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s?

Respuesta :

PastaMario
PastaMario PastaMario
  • 24-07-2017
Physics is my weakest subject, but it's worth a shot here. Hopefully the answer is right.

velocity(final) = velocity(initial) + acceleration * time
vf = vi + a * t
We want to bring the chihuahua to a stop in half a second. So, velocity(final) = 0 m/s. Its velocity(initial) = 3.3 m/s.

Solving for a, the acceleration.
0 m/s = 3.3 m/s + (a) * 0.5 s
a = -6.6 m/s^2

Force = mass * acceleration
F = m * a
We know the mass of the chihuahua and we just found the necessary acceleration.
Plug those in.
F = (3.6 kg) * (-6.6 m/s^2)

F = -23.76 N
Answer Link

Otras preguntas

The word percent (%) means " divided by _________?"
how did hitler become chancellor?
___ faults are caused by shear force
Is it true that all states celebrate Memorial Day on the same day. If not what can be the other date?
can someone please help with this page
In the book The True Confessions of Charlotte Doyle by Avi, in chapters 16 to 18, was Charlotte correct about the difficulty Zachariah would have taking Captain
For which value of x is undefined?
What European island nation is located at 20 degrees W and 63 degrees N?
A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity acting on the block (the weight) in water?
In the book The True Confessions of Charlotte Doyle by Avi, in chapters 16 to 18, was Charlotte correct about the difficulty Zachariah would have taking Captain