20pisraelyan
20pisraelyan 20pisraelyan
  • 23-07-2017
  • Mathematics
contestada

The law of cosines is a^2+b^2-2abcos(C). Find the value of 2abcos(C).
A. 37
B. -40
C. 40
D. 20

The law of cosines is a2b22abcosC Find the value of 2abcosC A 37 B 40 C 40 D 20 class=

Respuesta :

jdoe0001 jdoe0001
  • 23-07-2017
[tex]\bf \textit{Law of Cosines}\\ \quad \\ c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\\\\ -------------------------------\\\\ \begin{cases} c=2\\ a=4\\ b=5 \end{cases}\implies 2^2=4^2+5^2-(2ab)cos(C) \\\\\\ (2ab)cos(C)=4^2+5^2-2^2[/tex]

and surely you know how much that is.
Answer Link
noriegaevelyn45 noriegaevelyn45
  • 23-12-2020

Answer:

A. 37 i just took the quiz

Answer Link

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