How many different arrangements could be made using 4 characters if repetition is not allowed? assume your "alphabet" consists of the lower-case letters?

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24-06-2017
Mathematics

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How many different arrangements could be made using 4 characters if repetition is not allowed? assume your "alphabet" consists of the lower-case letters?

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mathmate mathmate · Answer 1 · 2017-06-25T05:28:02+02:00

mathmate mathmate

25-06-2017

Assume lower-case English alphabet used.
first letter: 26 choices
second letter: 25 choices
third letter: 24 choices
fourth letter : 23 choices
Total number of arrangements = 26*25*24*23=358800

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