Answer: The spring stretched by 80 cm.
Explanation:
Force exerted bu the box = 520N
Spring constant = k= 650 N/m
Meter by which spring stretched = x meters
Spring constant formula:
[tex]Force=k\times distance=k\times x[/tex]
[tex]x=\frac{520 N}{650 N/m}=0.8 m=80 cm (1 m=100 cm)[/tex]
The spring is stretched by 80 cm.
