Respuesta :

akaleti47
if x+5 is the base, the equation means (x+5)^2=36

clearly x+5=6

hence x=1
Tucon
   
[tex]\displaystyle\\ \bf\\ log_{x+5} 36 = 2\\\\ \Longrightarrow~~(x+5)^2 = 36\\\\ (x+5)^2 = 6^2\\\\ x+5= 6\\\\ x = 6 - 5 = \boxed{\bold{1}}[/tex]