Given the circle of center z
QR = 12 , ST = 12 , UZ = 8 and VZ = 2x - 6
AS shown in the figure:
ZY ⊥ ST and ZW ⊥ QR
Given QR = ST = 12
So,
the line segment UZ = line segment VZ
So,
2x - 6 = 8
2x = 8 + 6
2x = 14
x = 14/2 = 7
And ZY is bisects the line segment ST
So,
SV is half the line segment ST
SV = 0.5 * 12 = 6
So, the answer is :
x = 7
SV = 6
