OdellC590982 OdellC590982
  • 26-10-2022
  • Mathematics
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TakumiA706368 TakumiA706368
  • 26-10-2022

x² + 4x + 4 = 0

Find two numbers whose poduct gives 4 and sum gives 4

Replace the coefficient of x by the number

That is;

x² + 2x + 2x + 4 = 0

x(x+2) + 2(x+ 2) = 0

x+ 2 = 0

x = -2 twice

It has one solution

x² - 2x + 1 = 0

x² -x - x + 1 = 0

x(x - 1) - 1(x - 1) = 0

(x-1)(x-1) = 0

x = 1

It has one solution

x² + 6x + 5 = 0

x² + 5x + x + 5 = 0

x(x + 5) + 1 (x+ 5)

(x+5)(x+1) = 0

Either

x+5=0 or (x+1)=0

x = -5 or x = -1

It has two solutions

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