AmeilyaS53292 AmeilyaS53292
  • 25-10-2022
  • Mathematics
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jeriel leans a 26 foot ladder against a wall so that it forms an angle of 61 with the ground .

jeriel leans a 26 foot ladder against a wall so that it forms an angle of 61 with the ground class=

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MarkitaI521230 MarkitaI521230
  • 25-10-2022

To solve this problem we will use the following diagram:

where d is the distance between the base of the ladder and the wall.

Using the cosine we get:

[tex]\cos 61^{\circ}=\frac{d}{26ft}.[/tex]

Multiplying the above equation by 26ft we get:

[tex]\begin{gathered} \cos 61^{\circ}\times26ft=\frac{d}{26ft}\times26ft\text{.} \\ d=26ft\cdot\cos 61^{\circ}\text{.} \end{gathered}[/tex]

Then:

[tex]d\approx12.60505013ft\approx12.61ft.[/tex]

Answer: 12.61.

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