Solution
Let the required length be p
[tex]\begin{gathered} Angle\text{ given = 9}^0 \\ Opposite=125ft \\ Hypotenuse\text{ =p} \\ sin\text{ 9 = }\frac{opposite\text{ }}{hypotenuse} \\ \\ sin\text{ 9=}\frac{125}{p} \\ \\ p=\frac{125}{sin9} \\ p=799.057\text{ ft} \\ p=799.06\text{ ft\lparen nearest hundreth\rparen} \end{gathered}[/tex]
The answer is 799.06 ft
