The given logarithm is:
[tex]\log_47[/tex]
The chase of base is given by the following formula:
[tex]\log_ba=\frac{\log_xa}{\log_xb}=\frac{\ln a}{\ln b}[/tex]
If we replace a=7 and b=4, we obtain:
[tex]\begin{gathered} \log_47=\frac{\ln7}{\ln4}=\frac{1.946}{1.386} \\ \\ \log_47=1.404 \end{gathered}[/tex]
The answer is 1.404
