The given information is:
Length of the rectangle L=24 yd
Width of the rectangle W=12 yd.
The perimeter of a rectangle is given by the following formula:
[tex]P=2L+2W[/tex]
Replace the given values and solve for P:
[tex]\begin{gathered} P=2\times24yd+2\times12yd \\ P=48yd+24yd \\ P=72yd \end{gathered}[/tex]
The answer is 72 yd.
