JayseR353851 JayseR353851
  • 25-10-2022
  • Mathematics
contestada

What values of b satisfy 4(3b+2)^2=64

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JocelynF371883 JocelynF371883
  • 25-10-2022
[tex]4(3b+2)^2=64[/tex]

solve for b:

take the square root of both sides:

[tex]\begin{gathered} \sqrt[]{4(3b+2)^2}=\sqrt[]{64} \\ \sqrt[]{4}\cdot\sqrt[]{(3b+2)^2}=\pm8 \\ 2(3b+2)=\pm8 \\ 6b+4=\pm8 \\ so\colon \\ b=\frac{\pm8-4}{6} \end{gathered}[/tex]

therefore:

[tex]\begin{gathered} b=\frac{2}{3} \\ or \\ b=-2 \end{gathered}[/tex]

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