ShaindyD673429 ShaindyD673429
  • 25-10-2022
  • Physics
contestada

What force in newtons must be applied perpendicular to the end of a wrench handle 25 cm long to produce torque 500N *cm

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YiU765070 YiU765070
  • 25-10-2022

ANSWER

20 N

EXPLANATION

Torque produced by a force F perpendicular to a lever arm with length r is:

[tex]\tau=F\cdot r[/tex]

In this case we have to find F, when τ = 500 N*cm and r = 25cm:

[tex]500Ncm=F\cdot25\operatorname{cm}[/tex]

Solving for F:

[tex]F=\frac{500Ncm}{25\operatorname{cm}}=20N[/tex]

To produce a torque of 500N*cm, a perpendicular force of 20N must be applied

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