Recall the following properties of exponentials:
[tex]\begin{gathered} (a^n)^m=a^{n\times m} \\ \\ a^{-n}=\frac{1}{a^n} \end{gathered}[/tex]
Use these two properties in that order to find another expression for the same number:
[tex](4^{-5})^3=4^{-5\times3}=4^{-15}=\frac{1}{4^{15}}[/tex]
Therefore, the correct choice is option A)
[tex]\frac{1}{4^{15}}[/tex]
