ShezaJ679987 ShezaJ679987
  • 25-10-2022
  • Mathematics
contestada

can you please help me

Respuesta :

LeanaA469092 LeanaA469092
  • 25-10-2022

first we will find the missing side with the pythagorean theorem:

[tex]\begin{gathered} a^2+b^2=c^2 \\ a^2+4^2=5^2 \\ a^2+16=25 \\ a^2+16-16=25-16 \\ a^2=9 \\ a=\sqrt[]{9}=3 \end{gathered}[/tex]

for sin x

[tex]\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{3}{5}[/tex]

for cos x

[tex]\cos x=\frac{adjacent}{hypotenuse}=\frac{4}{5}[/tex]

for tan x

[tex]\tan x=\frac{opposite}{adjacent}=\frac{3}{4}[/tex]

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