DelvonE204884 DelvonE204884

25-10-2022
Mathematics

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suppose s is between r and t use the segment addition postulate to solve for each variable RS equals 2z plus 6 St equals 4z - 3 RT = 5z + 12

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AnyF74729 AnyF74729

25-10-2022

If s is between r and t, then:

RS + ST = RT

Where RS = 2z + 6

ST = 4z - 3

RT = 5z + 12

So, we get:

(2z + 6) + (4z - 3) = 5z + 12

Solving for z, we get:

2z + 6 + 4z - 3 = 5z + 12

6z + 3 = 5z + 12

6z + 3 - 5z = 12

z + 3 = 12

z = 12 - 3

z = 9

Answer: z = 9

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