SyasiaA701454 SyasiaA701454
  • 25-10-2022
  • Mathematics
contestada

g(x)= x^2+3h(x)= 4x-3Find (g-h) (1)

Respuesta :

DavudB197185 DavudB197185
  • 25-10-2022

Given:-

[tex]g(x)=x^2+3,h(x)=4x-3[/tex]

To find:-

[tex](g-h)(1)[/tex]

At first we find the value of (g-h)(x), so we get,

[tex]\begin{gathered} (g-h)(x)=g(x)-h(x) \\ =x^2+3-(4x-3) \\ =x^2+3-4x+3 \\ =x^2-4x+6 \end{gathered}[/tex]

So the value of,

[tex](g-h)(x)=x^2-4x+6[/tex]

So the value of (g-h)(1) is,

[tex]\begin{gathered} (g-h)(x)=x^2-4x+6 \\ (g-h)(1)=1^2-4\times1+6 \\ (g-h)(1)=1-4+6 \\ (g-h)(1)=7-4 \\ (g-h)(1)=3 \end{gathered}[/tex]

So the required value is,

[tex](g-h)(1)=3[/tex]

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