Given a quadratic equation in vertex form
[tex]y=a(x-h)^2+k[/tex][tex]\begin{gathered} \text{ wh}ere\text{ a, h, and k are constants, } \\ \text{then the point (h, k) is the vertex of the function} \end{gathered}[/tex]In our case,
[tex]y=(x+10)^2+2[/tex]h = -10, and k= 2
Therefore the vertex is (-10, 2)
