[tex]\begin{gathered} -2x+3y=-12 \\ 2x+y=4 \\ \text{adding} \\ 4y=-8 \\ \end{gathered}[/tex]
solve for y
[tex]\begin{gathered} \frac{4y}{4}=-\frac{8}{4} \\ y=-2 \end{gathered}[/tex]
then, solve for x
[tex]\begin{gathered} 2x-2=4 \\ 2x-2+2=4+2 \\ 2x=6 \\ \frac{2x}{2}=\frac{6}{2} \\ x=3 \end{gathered}[/tex]
x = 3
y = -2
