Given:
Line equation, y=1+4x
The point, (1,2)
To find the slope intercept form:
The general slope intercept form is, y=mx+b.
First to find m:
From the line equation,
y=4x+1
We have, m=4
Next to find b:
Substitute m=4, and (1,2) in the general intercept form is,
[tex]\begin{gathered} (2)=4(1)+b \\ 2=4+b \\ b=-2 \end{gathered}[/tex]
Now, substitute m=4 and b=-2 in the slope intercept form
Thus, the slope intercept form is,
[tex]y=4x-2[/tex]
