cesnal0002 cesnal0002
  • 25-08-2022
  • Mathematics
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(4^7/5^2)^3 i Don't get it

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devishri1977
devishri1977 devishri1977
  • 25-08-2022

Answer:

[tex]\sf \dfrac{4^{21}}{5^6}[/tex]

Step-by-step explanation:

Exponent Law:  

       [tex]\sf \boxed{\left(\dfrac{a^m}{b^n}\right)^{x}=\dfrac{a^{m*x}}{b^{n*x}}}[/tex]

When any base is being multiplied by an exponent, distribute the exponent to each part of the base.

[tex]\sf \left(\dfrac{4^7}{5^2}\right)^{3}=\dfrac{4^{7*3}}{5^{2*3}}[/tex]

           [tex]\sf =\dfrac{4^{21}}{5^6}[/tex]

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