Answer:
[tex]y=\frac{4}{7}x+3[/tex]
Step-by-step explanation:
The gradient of line A is
[tex]\frac{-6-(-2)}{-7-0}=\frac{4}{7}[/tex]
Parallel lines have the same gradient, so m = 4/7.
Substituting the coordinates of P into y = mx + c,
[tex]3=c \implies y=\frac{4}{7}x+3[/tex]
