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You are given the following three half-reactions:(1) Fe³⁺(aq) + e⁻ ⇄ Fe²⁺(aq) (2) Fe²⁺(aq) +2e⁻ ⇄ Fe(s) (3) Fe³⁺(aq) +3e⁻ ⇄ Fe(s) (a) Use E°half-cell values for (1) and (2) to find E°half-cell for (3).

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tanisharawat014

The cell potential of the equation-3 is 0.33 volts .

Given,

1)  Fe3+(aq) +e =Fe2+(aq)

2) Fe2+(aq) +2e = Fe(s)

3) Fe3+(aq) +3e = Fe(s)

We know the E0 half-cell value of euation-1 is 0.77 volts .

And value of E0 half cell of equation-2 is -0.44 volts .

By resolving or adding equation 1 and 2 we will get equation-3 ,

Thus , the value of the E0 half cell of equation-3 is given by ,

E0cell = 0.77-0.44 = 0.33 volts

Hence the E0 half cell of equation-3 is 0.33 volts .

Learn more about cell potential here :

brainly.com/question/19036092

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