briannab5377 briannab5377
  • 23-08-2022
  • Chemistry
contestada

What is the value of the equilibrium constant for the reaction between each pair at 25°C?(b) Sn(s) and Pb²⁺(aq)

Respuesta :

rafikiedu08 rafikiedu08
  • 27-08-2022

Temperature = 25° C = 298 K

E°cell for the reaction = Ereduction - Eoxidation = -0.13 + 0.14 = 0.01

As we know, the equilibrium constant is,

K = [tex]\frac{nf}{RT} E[/tex]°cell

[tex]K = \frac{2 * 96500}{8.314 *298}[/tex] × [tex]0.01[/tex]

K = 0.778988

So, the equilibrium constant for the reaction is 0.778988.

To learn more about equilibrium constant visit: https://brainly.com/question/13127425

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