maywhq maywhq
  • 24-07-2022
  • Mathematics
contestada

Help me please with this question

Help me please with this question class=

Respuesta :

princechimezirim096
princechimezirim096 princechimezirim096
  • 24-07-2022

Answer:

[tex]y = \sqrt{ \frac{\pi \: x - A {}^{} }{\pi} } [/tex]

Step-by-step explanation:

To make y subject of formular, we place y in terms of other variables.

[tex] A = \pi \: x {}^{2} - \pi \: y {}^{2} \\ making \: y \: subject \\ A + \pi \: y {}^{2} = \pi \: x {}^{2} \\ \pi \: y {}^{2} = \pi \: x {}^{2} - A \\ Dividing \: bothsides \: by \: \pi \\ y {}^{2} = \frac{\pi \: x { - A}^{} }{\pi} \\ Squarerooting \: bothsides \\ y = \sqrt{ \frac{\pi \: x - A {}^{} }{\pi} } [/tex]

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