a) Substituting in n = 2,
[tex]\frac{3(2)^{2}}{2}=6[/tex]
b) Substituting in n = 5,
[tex]\frac{3(5)^{2}}{2}=\frac{75}{2}[/tex]
c) Setting the nth term to be greater than 50,
[tex]\frac{3n^{2}}{2}>50 \\ \\ n^{2} >\frac{100}{3} \\ \\ n>\frac{10}{\sqrt{3}} \\ \\ \lceil n \rceil = 6[/tex]
