emanuel20971
emanuel20971 emanuel20971
  • 24-06-2022
  • Chemistry
contestada

How many grams of aluminum
chloride, AlCl3, form when 0.25 mol
Al react?

2AI+ 3Cl₂ → 2AICI 3

[?] g AICI 3

Respuesta :

Medunno13
Medunno13 Medunno13
  • 24-06-2022

From the equation, we know that for every 2 moles of aluminum consumed, 2 moles of aluminum chloride are produced.

This means that if 0.25 moles of Al react, then 0.25 moles of aluminum chloride are produced.

  • The atomic mass of Al is 26.9815385 g/mol.
  • The atomic mass of Cl is 35.45 g/mol.

So, the formula mass of aluminum chloride is:

  • 26.9815385+3(35.45)=133.3315385 g/mol.

Thus, 0.25 moles have a mass of:

  • (133.3315385)(0.25), which is about 33 g (to 2 sf)
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