khuloodahmad2006 khuloodahmad2006
  • 22-06-2022
  • Mathematics
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Medunno13
Medunno13 Medunno13
  • 28-06-2022

Question 1: There's no directive, can't answer this

Question 2: Dividing the numerator and denominator by x, we get the limit is equal to:

[tex]\lim_{x \to -\infty} \frac{-\sqrt{1+\frac{5}{x}+\frac{1}{x^2}}+3}{4+\frac{7}{x}}\\\\=\frac{\lim_{x \to -\infty} \left(-\sqrt{1+\frac{5}{x}+\frac{1}{x^2}}+3 \right)}{\lim_{x \to -\infty} \left(4+\frac{7}{x} \right)}\\\\=\frac{2}{4}=\boxed{1/2}[/tex]

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