The values of x in f(x) = 3|x - 2| + 6 when f(x) = 18 are 6 and -2
How to determine the value of x?
The function is given as:
f(x) = 3|x - 2| + 6
The value of f(x) is
f(x) = 18
So, we have:
3|x - 2| + 6 = 18
Subtract 6 from both sides
3|x - 2| = 12
Divide both sides by 3
|x - 2| = 4
Remove the absolute bracket
x - 2 = 4 or x - 2 = -4
Add 2 to both sides
x = 6 or x = -2
Hence, the values of x are 6 and -2
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