since it's diameter is 24, its radius must be 12.
[tex]\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12 \end{cases}\implies SA=4\pi (12)^2\implies SA=576\pi[/tex]
now, that's for a sphere, for a hemisphere with the same radius it'd just be half that or 288Ï€, now let's add the area of the circular base.
[tex]\stackrel{\textit{\LARGE Areas}}{\stackrel{hemisphere}{288\pi} ~~ + ~~\stackrel{circular~base}{\pi (12)^2}}\implies 288\pi ~~ + ~~144\pi \implies 432\pi[/tex]
The total surface area of the hemisphere is 288Ï€. The area that include both surface area of hemisphere and the base of the total area is 432Ï€.
A hemisphere is "half the part of sphere".
According to the question,
The diameter of greater circle is 24 this implies radius of circle is 12.
Surface area of sphere = 4πr²
= 4×π × (12)²
= 576Ï€.
Surface area of sphere is 576Ï€
Surface area of Hemisphere is half of the surface area of sphere.
(576Ï€)/2 = 288Ï€
In order to include the base in the total area only if add surface area of hemisphere and area of circle.
surface area of hemisphere + rea of circle = 288π + π(r)²
= 288π + π(12)²
= 288Ï€ + 144Ï€
= 432Ï€
Hence, the total surface area of the hemisphere is 288Ï€. The area that include both surface area of hemisphere and the base of the total area is 432Ï€.
Learn more about hemisphere here
https://brainly.com/question/16724000
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